Optimal. Leaf size=264 \[ \frac{a \left (5 a^2 (3 A+2 C)+6 b^2 (5 A+4 C)\right ) \sin (c+d x)}{15 d}+\frac{b \left (6 a^2 C+5 b^2 (6 A+5 C)\right ) \sin (c+d x) \cos ^3(c+d x)}{120 d}+\frac{a \left (C \left (a^2+12 b^2\right )+15 A b^2\right ) \sin (c+d x) \cos ^2(c+d x)}{15 d}+\frac{b \left (6 a^2 (4 A+3 C)+b^2 (6 A+5 C)\right ) \sin (c+d x) \cos (c+d x)}{16 d}+\frac{1}{16} b x \left (6 a^2 (4 A+3 C)+b^2 (6 A+5 C)\right )+\frac{C \sin (c+d x) \cos ^2(c+d x) (a+b \cos (c+d x))^3}{6 d}+\frac{a C \sin (c+d x) \cos ^2(c+d x) (a+b \cos (c+d x))^2}{10 d} \]
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Rubi [A] time = 0.539327, antiderivative size = 264, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.161, Rules used = {3050, 3049, 3033, 3023, 2734} \[ \frac{a \left (5 a^2 (3 A+2 C)+6 b^2 (5 A+4 C)\right ) \sin (c+d x)}{15 d}+\frac{b \left (6 a^2 C+5 b^2 (6 A+5 C)\right ) \sin (c+d x) \cos ^3(c+d x)}{120 d}+\frac{a \left (C \left (a^2+12 b^2\right )+15 A b^2\right ) \sin (c+d x) \cos ^2(c+d x)}{15 d}+\frac{b \left (6 a^2 (4 A+3 C)+b^2 (6 A+5 C)\right ) \sin (c+d x) \cos (c+d x)}{16 d}+\frac{1}{16} b x \left (6 a^2 (4 A+3 C)+b^2 (6 A+5 C)\right )+\frac{C \sin (c+d x) \cos ^2(c+d x) (a+b \cos (c+d x))^3}{6 d}+\frac{a C \sin (c+d x) \cos ^2(c+d x) (a+b \cos (c+d x))^2}{10 d} \]
Antiderivative was successfully verified.
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Rule 3050
Rule 3049
Rule 3033
Rule 3023
Rule 2734
Rubi steps
\begin{align*} \int \cos (c+d x) (a+b \cos (c+d x))^3 \left (A+C \cos ^2(c+d x)\right ) \, dx &=\frac{C \cos ^2(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{6 d}+\frac{1}{6} \int \cos (c+d x) (a+b \cos (c+d x))^2 \left (2 a (3 A+C)+b (6 A+5 C) \cos (c+d x)+3 a C \cos ^2(c+d x)\right ) \, dx\\ &=\frac{a C \cos ^2(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{10 d}+\frac{C \cos ^2(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{6 d}+\frac{1}{30} \int \cos (c+d x) (a+b \cos (c+d x)) \left (2 a^2 (15 A+8 C)+a b (60 A+47 C) \cos (c+d x)+\left (6 a^2 C+5 b^2 (6 A+5 C)\right ) \cos ^2(c+d x)\right ) \, dx\\ &=\frac{b \left (6 a^2 C+5 b^2 (6 A+5 C)\right ) \cos ^3(c+d x) \sin (c+d x)}{120 d}+\frac{a C \cos ^2(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{10 d}+\frac{C \cos ^2(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{6 d}+\frac{1}{120} \int \cos (c+d x) \left (8 a^3 (15 A+8 C)+15 b \left (6 a^2 (4 A+3 C)+b^2 (6 A+5 C)\right ) \cos (c+d x)+24 a \left (15 A b^2+\left (a^2+12 b^2\right ) C\right ) \cos ^2(c+d x)\right ) \, dx\\ &=\frac{a \left (15 A b^2+\left (a^2+12 b^2\right ) C\right ) \cos ^2(c+d x) \sin (c+d x)}{15 d}+\frac{b \left (6 a^2 C+5 b^2 (6 A+5 C)\right ) \cos ^3(c+d x) \sin (c+d x)}{120 d}+\frac{a C \cos ^2(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{10 d}+\frac{C \cos ^2(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{6 d}+\frac{1}{360} \int \cos (c+d x) \left (24 a \left (5 a^2 (3 A+2 C)+6 b^2 (5 A+4 C)\right )+45 b \left (6 a^2 (4 A+3 C)+b^2 (6 A+5 C)\right ) \cos (c+d x)\right ) \, dx\\ &=\frac{1}{16} b \left (6 a^2 (4 A+3 C)+b^2 (6 A+5 C)\right ) x+\frac{a \left (5 a^2 (3 A+2 C)+6 b^2 (5 A+4 C)\right ) \sin (c+d x)}{15 d}+\frac{b \left (6 a^2 (4 A+3 C)+b^2 (6 A+5 C)\right ) \cos (c+d x) \sin (c+d x)}{16 d}+\frac{a \left (15 A b^2+\left (a^2+12 b^2\right ) C\right ) \cos ^2(c+d x) \sin (c+d x)}{15 d}+\frac{b \left (6 a^2 C+5 b^2 (6 A+5 C)\right ) \cos ^3(c+d x) \sin (c+d x)}{120 d}+\frac{a C \cos ^2(c+d x) (a+b \cos (c+d x))^2 \sin (c+d x)}{10 d}+\frac{C \cos ^2(c+d x) (a+b \cos (c+d x))^3 \sin (c+d x)}{6 d}\\ \end{align*}
Mathematica [A] time = 0.687322, size = 252, normalized size = 0.95 \[ \frac{120 a \left (a^2 (8 A+6 C)+3 b^2 (6 A+5 C)\right ) \sin (c+d x)+15 b \left (48 a^2 (A+C)+b^2 (16 A+15 C)\right ) \sin (2 (c+d x))+1440 a^2 A b c+1440 a^2 A b d x+90 a^2 b C \sin (4 (c+d x))+1080 a^2 b c C+1080 a^2 b C d x+80 a^3 C \sin (3 (c+d x))+240 a A b^2 \sin (3 (c+d x))+300 a b^2 C \sin (3 (c+d x))+36 a b^2 C \sin (5 (c+d x))+30 A b^3 \sin (4 (c+d x))+360 A b^3 c+360 A b^3 d x+45 b^3 C \sin (4 (c+d x))+5 b^3 C \sin (6 (c+d x))+300 b^3 c C+300 b^3 C d x}{960 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.022, size = 249, normalized size = 0.9 \begin{align*}{\frac{1}{d} \left ( A{b}^{3} \left ({\frac{\sin \left ( dx+c \right ) }{4} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) +C{b}^{3} \left ({\frac{\sin \left ( dx+c \right ) }{6} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{5\,dx}{16}}+{\frac{5\,c}{16}} \right ) +aA{b}^{2} \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) +{\frac{3\,Ca{b}^{2}\sin \left ( dx+c \right ) }{5} \left ({\frac{8}{3}}+ \left ( \cos \left ( dx+c \right ) \right ) ^{4}+{\frac{4\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}}{3}} \right ) }+3\,A{a}^{2}b \left ( 1/2\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) +1/2\,dx+c/2 \right ) +3\,{a}^{2}bC \left ( 1/4\, \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+3/2\,\cos \left ( dx+c \right ) \right ) \sin \left ( dx+c \right ) +3/8\,dx+3/8\,c \right ) +A{a}^{3}\sin \left ( dx+c \right ) +{\frac{{a}^{3}C \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.02193, size = 328, normalized size = 1.24 \begin{align*} -\frac{320 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a^{3} - 720 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{2} b - 90 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{2} b + 960 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} A a b^{2} - 192 \,{\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} C a b^{2} - 30 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} A b^{3} + 5 \,{\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} - 60 \, d x - 60 \, c - 9 \, \sin \left (4 \, d x + 4 \, c\right ) - 48 \, \sin \left (2 \, d x + 2 \, c\right )\right )} C b^{3} - 960 \, A a^{3} \sin \left (d x + c\right )}{960 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.58444, size = 450, normalized size = 1.7 \begin{align*} \frac{15 \,{\left (6 \,{\left (4 \, A + 3 \, C\right )} a^{2} b +{\left (6 \, A + 5 \, C\right )} b^{3}\right )} d x +{\left (40 \, C b^{3} \cos \left (d x + c\right )^{5} + 144 \, C a b^{2} \cos \left (d x + c\right )^{4} + 80 \,{\left (3 \, A + 2 \, C\right )} a^{3} + 96 \,{\left (5 \, A + 4 \, C\right )} a b^{2} + 10 \,{\left (18 \, C a^{2} b +{\left (6 \, A + 5 \, C\right )} b^{3}\right )} \cos \left (d x + c\right )^{3} + 16 \,{\left (5 \, C a^{3} + 3 \,{\left (5 \, A + 4 \, C\right )} a b^{2}\right )} \cos \left (d x + c\right )^{2} + 15 \,{\left (6 \,{\left (4 \, A + 3 \, C\right )} a^{2} b +{\left (6 \, A + 5 \, C\right )} b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{240 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 7.44937, size = 668, normalized size = 2.53 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.20546, size = 292, normalized size = 1.11 \begin{align*} \frac{C b^{3} \sin \left (6 \, d x + 6 \, c\right )}{192 \, d} + \frac{3 \, C a b^{2} \sin \left (5 \, d x + 5 \, c\right )}{80 \, d} + \frac{1}{16} \,{\left (24 \, A a^{2} b + 18 \, C a^{2} b + 6 \, A b^{3} + 5 \, C b^{3}\right )} x + \frac{{\left (6 \, C a^{2} b + 2 \, A b^{3} + 3 \, C b^{3}\right )} \sin \left (4 \, d x + 4 \, c\right )}{64 \, d} + \frac{{\left (4 \, C a^{3} + 12 \, A a b^{2} + 15 \, C a b^{2}\right )} \sin \left (3 \, d x + 3 \, c\right )}{48 \, d} + \frac{{\left (48 \, A a^{2} b + 48 \, C a^{2} b + 16 \, A b^{3} + 15 \, C b^{3}\right )} \sin \left (2 \, d x + 2 \, c\right )}{64 \, d} + \frac{{\left (8 \, A a^{3} + 6 \, C a^{3} + 18 \, A a b^{2} + 15 \, C a b^{2}\right )} \sin \left (d x + c\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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